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3 years ago

8

Help me please, what are the like terms?

1 answer:

andriy [413]3 years ago

4 0

Step-by-step explanation:

Like terms are are terms whose variables (and their exponents such as the 2 in x 2) are the same. In other words, terms that are "like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different.

So like in your picture x and x would be like terms... your picture helps as well to identify your like terms because your like terms have the same background color to there particular rectangle.

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How do you do this problem

Ainat [17]

You divide (1354.5 kg of potatoes) by (12 stores in the Bronx).

The quotient is ________ kg of potatoes per store in the Bronx.

The division is easy to do with your pencil or your calculator.

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3 years ago

Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap

pogonyaev

Answer:

Rate of increase in height = $\frac{dh}{dt}=0.3156ft/min$

Step-by-step explanation:

we know that volume of a cone is given by

$V=\frac{1}{12}\pi d^{2}h$

It is Given that diameter equals height thus we have

$V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}$

Differentiating both sides with respect to time we get

$\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})$

Applying values and solving for $\frac{dh}{dt}$ we get

$\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min$

8 0

3 years ago

Van is studying the effects of an indoor pool

Artyom0805 [142]

Answer:

The answer is C

Step-by-step explanation:

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7 0

3 years ago

URGENT!! Really need help on this test

Anuta_ua [19.1K]

Answer:

x=17

Step-by-step explanation:

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3 years ago

John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$

Speed of water in downstream

$(15+x)\text{ kph}$

Relation:

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}$

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel 140 km downstream

$\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9$

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0

3 years ago