All categories

3 years ago

Help me please, what are the like terms?

Mathematics

1 answer:

andriy [413]3 years ago

4 0

Step-by-step explanation:

Like terms are are terms whose variables (and their exponents such as the 2 in x 2) are the same. In other words, terms that are "like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different.

So like in your picture x and x would be like terms... your picture helps as well to identify your like terms because your like terms have the same background color to there particular rectangle.

You might be interested in

Can someone please solve FAST I have 5 minutes

Hunter-Best [27]

Answer:

no time left sorry

Step-by-step explanation:

7 0

3 years ago

The denominator of a fraction is 9 more than the numerator. if both the numerator and the denominator are decreased by 1 the res

yarga [219]

X/x+9 (original fraction)

x+1/ x+10 = 4/13

x+1=4 so x=3 and x+10=13 so again x=3

now that you have the value of x, substitute it into the original fraction to get:

3/12

5 0

3 years ago

11 points Please answer quick.

ICE Princess25 [194]

Answer:

$\boxed{x^4 + x^2 + x}$

Step-by-step explanation:

$\frac{x^5 - x^4 + x^3 -x^2 + x - 1}{x - 1}$

$= \frac{(x - 1)(x^4 + x^2 + x)}{x - 1}$

$= x^4 + x^2 + x$

Happy to help :)

5 0

3 years ago

Question 15

larisa86 [58]

Answer:

The correct option is (C).

Step-by-step explanation:

According to the Central Limit Theorem if we have n unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

μ = 3.5

σ = 1.7078

n = 400 = number of times the experiment is repeated.

As the sample size is quite large, i.e. n = 400 > 30 the central limit theorem can be used to approximate the sampling distribution of the sample mean.

The mean of the distribution of sample means is:

$\mu_{\bar x}=\mu=3.5$

The standard deviation of the distribution of sample mean is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{1.7078}{\sqrt{400}}=0.0854$

The distribution of the sample mean is:

$\bar X\sim N(\mu = 3.5,\ \sigma=0.0854)$ .

Thus, the correct option is (C).

4 0

3 years ago

-6 < 2t - 5 < 3 Solve for T

natulia [17]

Answer:

I think it's 7

Step-by-step explanation:

-6 < 2T (-5+5) < 3+5

-6 < 2T < 8

+6 < 2T < 8 + 6

0 < 2T < 14

0 < ÷ 2 < ÷ 2

0 < T < 7

-0 < T < -0

T = 7

4 0

4 years ago