Answer/Step-by-step explanation:
1. ∠XVR = 180 - <XVW (angle on a straight line)
∠XVR = 180 - 55°
∠XVR = 125°
2. ∠RVS = <XVW (Vertical angles are congruent)
∠RVS = 55°
3. ∠WVS = ∠XVR (vertical angles are congruent)
∠WVS = 125°
4. ∠RST = <R + <RVS (exterior angle theorem)
<RST = 55 + 55
<RST = 110°
5. ∠RSV = 180 - (<R + <RVS) (sum of triangle)
∠RSV = 180 - (55 + 55)
∠RSV = 70°
6. ∠VSU = <RST (vertical angles are congruent)
<VSU = 70°
7. ∠UST = <RSV (vertical angles)
<UST = 70°
8. ∠TUS = 180 - (<UST + <T) (sum of triangle)
<TUS = 180 - (70 + 71)
<TUS = 39°
The irrational number that can be added to pi to get a rational sum is PI.
Answer:
5.5 years old.
Step-by-step explanation:
Let D represent present age of Robert's dog and C represent present age of Karen's cat.
We have been given that Robert's dog is 4 years older than Karen's cat. We can represent this information in an equation as:

We are also told that in 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. After 3 years age of dog and cat would be
and
respectively.
We can represent this information in an equation as:

From equation (1), we will get:

Upon substituting this value in equation (2), we will get:

Combine like terms:





Therefore, Robert's dog is 5.5 years old right now.
Answer:
A. 
B. 
Step-by-step explanation:
A. The area of the shaded region = area of the whole large square - area of the 4 smaller squares
= (5x*5x) - 4(4*4)
Area of shaded region = 
B. The expression,
, is the difference of two perfect squares, 25x² and 64. Therefore, apply the rule of factoring difference of two perfect squares.
Thus, 
Therefore, the expression of the are of the shaded region can be expressed in factored form as:

The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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