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padilas [110]
3 years ago
10

Find the equation of the line that passes through points A and B

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

y= 2x - 1

Step-by-step explanation:

find the slope of the two points using the slope formula. then use one point with the slope to find b in y= mx + b

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Write an algebraic rule to describe the translation P(–8, 6)
yKpoI14uk [10]
T_(-8,6): (x,y) -> (x-8, y+6)
5 0
3 years ago
Based on the data table, which equation accurately represents the situation?
8090 [49]

Answer:

The equation of the line is:

y = 28x

Hence, option C is correct.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the table

Gallons               Miles Driven

8                          224

10                         280

4                           112

Finding the slope between any two points, let say (8, 224) and (10, 280)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(8,\:224\right),\:\left(x_2,\:y_2\right)=\left(10,\:280\right)

m=\frac{280-224}{10-8}

m=28

now substituting (8, 224) and m = 28 in the slope-intercept form of line equation

y = mx+b

224 = 28(8) + b

224 = 224 + b

b = 0

Thus, the y-intercept b = 0

now substituting b = 0 and m = 28  in the slope-intercept form of line equation

y = mx+b

y = 28x+0

y = 28x

Therefore, the equation of the line is:

y = 28x

Hence, option C is correct.

7 0
3 years ago
Solve the matrix and prove that it is equal 0​
Art [367]

Step-by-step explanation:

\underline{ \underline{ \text{Given}}}  :

  • \tt{ {A}^{T}  = \begin{bmatrix} 2 &  - 4 \\ 4 & 3 \\ \end{bmatrix}}

\underline{ \underline { \text{To \: Find}}} :

  • \sf{ {A}^{2}  - 5A+ 22I= 0}

\underline{ \underline{ \text{Solution}}} :

The new matrix obtained from a given matrix by interchanging it's rows and columns is called the transposition of matrix. It is denoted by \sf{ {A}^{T}}. Again , Interchange it's rows and columns in order to find ' A '.

\tt{A = \begin{bmatrix} 2 &  4 \\  - 4 & 3 \\ \end{bmatrix}}

Now , LEFT HAND SIDE ( L.H.S )

\tt{ {A}^{2}  - 5A+ 22I}

Here, I refers to identity matrix. A diagonal matrix in which all the elements of leading diagonal are 1 ( unit ) is called unit or identity matrix.

⟼ \begin{bmatrix} 2 &   4 \\  - 4 & 3 \\ \end{bmatrix} \times \begin{bmatrix} 2 &  4 \\ -  4 & 3 \\ \end{bmatrix} - 5 \times \begin{bmatrix} 2 &   4 \\  - 4 & 3 \\ \end{bmatrix} + 22 \times \begin{bmatrix} 1 &   0 \\  0 & 1\\ \end{bmatrix}

⟼ \begin{bmatrix} 2  \times 2 + 4 \times ( - 4)&   2  \times 4 + 4 \times 3 \\  - 4 \times 2 + 3 \times ( - 4) &  - 4  \times 4 + 3 \times 3 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20& 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} 4 + ( - 16) &   8 + 12 \\   - 8 + ( - 12) &  - 16 + 9 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} - 12 &   20\\  - 20&  - 7 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix}  - 22 &   0 \\  0&  - 22 \\ \end{bmatrix}  + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix}  - 22 + 22 &   0 + 0 \\  0 + 0 &  - 22  + 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} 0 &   0\\  0 & 0 \\ \end{bmatrix}

⟼ \sf{0}

RIGHT HAND SIDE ( R.H.S ) : 0

L.H.S = R.H.S [ Hence , proved ! ]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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4 0
3 years ago
What is the answer? 236,272 round to the nearest ten thousand
mr_godi [17]
The answer is just 236,000 I hope it helps and is right
8 0
3 years ago
There are 875 members in an astronomy club. 350 of the members are female. What percentage of the members are males?
zaharov [31]
875: 100% = 350: x%
875x = 350 * 100
875x = 35000
x = 35000/875
x= 40% - that is the percentage of female members
Which means that the percentage of the members who are male is 60%. 
3 0
4 years ago
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