Answer:
a. (x^3+8)(x^2-4)
b. x=1 and x=1/2
Step-by-step explanation:
a. (x^3+8)(x^2-4) = x^5-4x^3+8x^2-32 [foil method: first,outside,inside,last]
b. use quadratic formula: -b +/- square root b^2-4ac / 2a
2=a; -3=b; 1=c
-(-3) + square root (-3)^2 - 4(2)(1) / 2(2)
3 + 1 / 4 = 4/4 = 1
3 - 1/4 = 2/4 = 1/2
Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base = ![\sqrt[3]{3}\times s^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%20s%5E%7B2%7D)
= ![\sqrt[3]{3}\times 2^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%202%5E%7B2%7D)
On solving we get:
Area of the base(b) = 
Then, we find the perimeter(p) :
Perimeter = s × 6

Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.




As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².
11ft 5.79 inches but.I dont know how much extra the foot is
Answer:
Step-by-step explanation: