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Ray Of Light [21]
3 years ago
11

Ron’s class donated d dollars to a local charity. Danny’s class donated 21% more than Ron’s class. Which expression shows the am

ount Danny’s class donated in terms of the amount donated by Ron’s class?
Mathematics
1 answer:
Savatey [412]3 years ago
6 0
DX1.21 because 1.21 means 21 percent more than d

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A downtown parking lot charges $5 per hour
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Parking charges for first 2hours =$5 per hour after 2 hours parking charges = $2.50per hour
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2 years ago
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The width of a rectangle is 5 meters less than its length. The area is 84 square
VARVARA [1.3K]

Answer:

12 and 7 meters

Step-by-step explanation:

The area is 84 square meters and the width is 5 meters less than the length. 12 is the length and 7 is the width. 7 is 5 less than 12, and 12*7=84.

The length is 12 and the width is 7

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3 years ago
Area of a regular hexagon with an apothem of 15 cm
Anton [14]

Answer:

area = 779.4 cm²

Step-by-step explanation:

divide it into 6 equal equilateral triangles. Each corner of a triangle will be 60°.

tan 60° = 15/x

1.7321 = 15/x

x = 8.66 (this is one-half of the base of the triangle)

base = 17.32 cm

area of one triangle = 1/2(17.32)(15) = 129.9 cm²

129.9(6) = 779.4 cm²   (because 6 triangles make up the hexagon)

8 0
3 years ago
The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​
sashaice [31]

Answer:

Hello,

Step-by-step explanation:

Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}

5 0
3 years ago
Triangle J K L is shown. Angle K L J is a right angle. The length of hypotenuse K J is 10.9 centimeters and the length of L J is
scZoUnD [109]

Answer:

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

Step-by-step explanation:

From the given triangle JKL;

Hypotenuse KJ = 10.9

Length LJ is the opposite = 8.9cm

The angle LKJ is the angle opposite to side KJ = x

Using the SOH CAH TOA Identity;

sin theta = opp/hyp

sin LKJ = LJ/KJ

Sinx = 8.9/10.9

x = arcsin(8.9/10.9)

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

7 0
3 years ago
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