The two x-values to your equation is
x=2 and x=-0.5
Add 9 to both sides
So
33=2x
Divide both sides by 2
So
X=16.5
78.3-54.6=23.7, which means the answer is 23.7.
Steps:
1. Draw a number line and put the numbers 1 and 2. (Do not put the numbers very close together)
2. Between 1 and 2 put 1/6, 2/6, 3/6, 4/6, 5,6, and 6/6. If they wanted it into seventh sense then you would do the same thing but split it into 7.
*I will send you a pic of what I mean
Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
