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3 years ago

The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?

Mathematics

2 answers:

bearhunter [10]3 years ago

7 0

Answer:

The student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

$P = 2l + 2w$

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are $\sqrt{50a^3b^2}$ and $\sqrt{200a^3}\:\:$ .

Here is the student's solution:

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

$=10ab\sqrt{2a}+20a\sqrt{2a}$

$=30ab\sqrt{2a}$

The student made an error in calculating $30ab\sqrt{2a}+20a\sqrt{2a}$ , because $30ab\sqrt{2a}+20a\sqrt{2a}$ are not like terms.

Hence, $30ab\sqrt{2a}+20a\sqrt{2a}$ can not be simplified to $30ab\sqrt{2a}$

Therefore, the student incorrectly simplified $30ab\sqrt{2a}+20a\sqrt{2a}$ .

Thus, option D is correct.

<u></u>

<u>Here is the correct Solution:</u>

$2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}$

$=10ab\sqrt{2a}+20a\sqrt{2a}$

vazorg [7]3 years ago

5 0

Answer: D

Step-by-step explanation

got it right on edg

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Solve the inequality.

maw [93]

The solution to inequality is less than the negative of 21. Then the correct option is C.

<h3>What is inequality?</h3>

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The inequality is given below.

−(1/3)x + 10 > 17

Then the solution to the inequality will be

−(1/3)x + 10 > 17

−(1/3)x > 17− 10

−(1/3)x > 7

When the sign is changed then the equality sign also changed.

(1/3)x < −7

x < − 21

The value of x is less than the negative of 21.

Thus, the correct option is C.

More about the inequality link is given below.

brainly.com/question/19491153

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2 years ago

A family consists of a father, a mother and 2 children. What is the probability that all 2 children are boys?

pashok25 [27]

Answer:

Step-by-step explanation:

The probability of having a boy is ½ and that of a girl is ½.

Probability of boy, boy is (pb*pb) and given pb to be ½ then we can prove the point as follows

For these two children

The options are as follows

1 boy(first) and 1 girl

2 boys

2 girls

1 girl( first) and 1 boy

These are four possible options and the option for two boys is 1 out of the four.

The probability of 2 boys is ½*½=¼

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3 years ago

The length of a rectangle is 3/2 units greater than its width. If the width is w, which expression gives the perimeter of the re

faltersainse [42]

W+w+(3/2+w)+(3/2+w)=perimeter
4w+6/2=perimeter

7 0

3 years ago

Read 2 more answers

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers

Line a passes through the points (-1,0) and (3,-8)<br> what’s the slope?

konstantin123 [22]

Answer: 2

Step-by-step explanation:

(x1,y1) = (-1,0)

(x2,y2) = (3,8)

m = (8–0)/(3-(-1))

m = 8/(3+1)

m = 8/4

m = 2

8 0

2 years ago