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mrs_skeptik [129]
3 years ago
8

2. There is a 50% chance that Elaine will be late to school, a 40% chance that she will be late to

Mathematics
1 answer:
Verdich [7]3 years ago
8 0

Answer:

50%

Step-by-step explanation:

Given that:

P(late) = P(L) = 50% = 0.5

P(Eat) = P(E) =?

P(LnE) = 40% = 0.4

P(LuE) = 60% = 0.6

P(LuE) = P(L) + P(E) - P(LnE)

0.6 = 0.5 + x - 0.4

0.6 = 0.1 + x

0.6 - 0.1 = x

0.5 = x

P(E) = 0.5

0.5 * 100% = 50%

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A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
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Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
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\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
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There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
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Step-by-step explanation:

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