2 years ago

A varies inversely as the square of B. If A is 1 when B is 3, find A when B is 5

Mathematics

1 answer:

RideAnS [48]2 years ago

6 0

Answer:

0.36

Step-by-step explanation:

A= K/B^2

K= A × B^2

K= 1 × 3^2

K= 1×9

K= 9

Therefore if B is 5 then A can be calculated as follows.

K= A × B^2

9= A × 5^2

9= A × 25

9= 25A

A= 9/25

A= 0.36

Hence A is 0.36

You might be interested in

Distribute! only 5 problems!

Dominik [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

PLZ HELP GIVING CORRECT ANSWER THE BRAINLIEST!!

beks73 [17]

Answer:

About 20.8

Step-by-step explanation:

form a triangle using each line

3 0

3 years ago

If an airplanes speed is 850mi/h what is it’s speed in m/s

Blizzard [7]

we are given

speed is 850mi/h

we know that

1 mile =1609.34 metre

1 hour = 3600 second

now, we can replace 1mi and 1hour

$850mi/h=850*\frac{1609.34}{3600} m/s$

now, we can solve it

379.98306

$850mi/h=379.98306 m/s$ ...........Answer

7 0

3 years ago

Read 2 more answers

B. The number of cats your teammates have as pets: 0, 1, 3,2

algol [13]

Ok so 1.2 is the answer you get if you divide them

and you can also say one because its counting by ones

7 0

3 years ago

If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc

grin007 [14]

$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112$

3 0

3 years ago