Two dice are rolled. Find the probability of the following event.
1 answer:
Answer: 5/18
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Explanation:
A = number of times we get 5 on the first die
B = number of times we get a sum of 6.
Refer to the sum of dice chart below. This chart represents every possible sum of two dice (eg: 1+1 = 2 in the top left corner or 6+6 = 12 in the bottom right corner).
Let's say the blue die is the first of the pair.
Locate 5 on the blue die and notice there are 6 occurrences when this happens. This corresponds to the 6 other possibilities for the red die. So we have A = 6.
Also notice how there are 5 occurrences of the sum "6" in the table. So B = 5.
We have A+B = 6+5 = 11 occurrences of either the first die is 5 or the sum is 6. However, we have to subtract off 1 because we double counted "6" when adding A and B.
So in reality we have 11-1 = 10 times this happens.
This is out of 36 total ways to roll two dice.
Therefore, the probability we want is 10/36 = 5/18
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so, bearing in mind that vertical angles are equal, thus ∡AED = ∡BEC, and we know that ∡BEC = 52 = ∡AED, so those two angles added up are 104°.
now, a circle has a total of 360°, if we take away those 104° from the red angles, what's leftover is just 256°, well, the green angles there are also vertical angles and thus twins, so each one will take half of 256°.
∡BEA = 128° = ∡CED.
