Answer:
Adaptations increase fitness.
Explanation:
Animals with the most fitness are most likely to survive. In a given population, there are small mutations that accumulate over time. If these mutations are useful in increasing fitness, they become adaptations that help increase fitness.
Answer:
492.3 cm³.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If P and n are constant, and have different values of T and V:
<em>(V₁T₂) = (V₂T₁).</em>
V₁ = 417.0 cm³, T₁ = 65°C + 273 = 338 K.
V₂ = ??? cm³, T₂ = 126°C + 273 = 399 K.
<em>∴ V₂ = (V₁T₂)/(T₁) =</em> (417.0 cm³)(399 K)/(338 K) = <em>492.3 cm³.</em>
Answer:
300
Explanation:
Multiply Length by value of 1000
There are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.
HOW TO CALCULATE NUMBER OF MOLES:
The number of moles of a sample of gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure of gas (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant (0.0821 Latm/molK)
- T = temperature (K)
According to this question;
- P = 760mmHg = 1 atm
- T = 100°C = 100 + 273 = 373K
- V = 250mL = 0.250L
- n = ?
1 × 0.250 = n × 0.0821 × 373
0.250 = 30.62n
n = 0.250 ÷ 30.62
n = 8.16 × 10-³mol
Therefore, there are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.
Learn more about number of moles at: brainly.com/question/4147359
6.5 is subtracted from each number.
9 - 6.5 = 2.5
2.5 - 6.5 = -4
-4 - 6.5 = -10.5
-10.5 - 6.5 = -17
or you could think of adding -6.5 to everything if that is easier for you to picture.
