Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =
2. percentage of s character in hybrid orbital =
3. percentage of s character in hybrid orbital =
Thus percentage of s-character in an sp hybrid is 50%.
Explanation:
i found this the question is different but I think the situation is same
Answer:
Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.
Explanation:
Percentage of element in compound :
(a) Urea,
Molar mass of urea = 60 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 2
(b) Ammonium nitrate,
Molar mass of ammonium nitrate = 80 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 2
(c) Nitric oxide, NO
Molar mass of nitric oxide = 30 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 1
(d) Ammonia,
Molar mass of ammona = 17 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 1
Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.