Answer:
Explanation:
1) Vanadium (IV) → V⁺⁴
Carbonate → CO₃⁻²
So , Vanadium (IV) Carbonate = V₂(CO₃)₄ or V(CO₃)₂
2) Tin (II) = Sn⁺²
Nitrite = NO₂⁻
So, Tin (II) Nitrate = Sn(NO₂)₂
3) Cobalt (III) = Co⁺³
Oxide = O⁻²
So , Cobalt (III) Oxide = Co₂O₃
4) Titanium (II) = Tn⁺²
Acetate = CH₃COO⁻
So , Titanium (II) Acetate = Tn(CH₃COO)₂ or Tn(C₂H₃O₂)₂
5) Vanadium (V) = V⁺⁵
Sulfide = S⁻²
So , Vanadium (V) Sulfide = V₂S₅
6) Chromium (III) = Cr⁺³
Hydroxide = OH⁻
So , Chromium (III) Hydroxide = Cr(OH)₃
7) Lithium = Li⁺
Iodide = I⁻
So , Lithium Iodide = LiI
8) Lead (II) = Pb⁺²
Nitride = N⁻³
So , Lead (II) Nitride = Pb₃N₂
9) Silver = Ag⁺
Bromide = Br⁻
So , Silver Bromide = AgBr
The answer is C but i might be wrong
1.)Boron
2.)Cadmium has 48 electrons not 121 Mercury has 80 And Copernicum so they all have no 121 electrons
3.)Hydrogen
Answer: The mass is 980.6g of Gold.
Explanation:
We begin by looking for the number of moles equivalent to 3.0 x 10^24 gold atoms.
Using the Avogadro's number,
6.02 x 10^23 atoms of gold make up 1 mole of gold.
3.0 x 10^24 atoms would make up: 1 / 6.02 x 10^23 x 3.0 x 10^24 = 4.98moles.
Now that we know the number of moles, we can then look for the mass using the formular:
Moles = mass/ molar mass
4.98 = mass / 196.9 (atomic mass of gold)
Making "mass" the subject of formula : mass = 4.98 x 196.9= 980.6g
