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Lelechka [254]
4 years ago
9

Determine if (2,5) Is a solution of -2x+4y=-16

Mathematics
2 answers:
tamaranim1 [39]4 years ago
8 0

Hi!

<h3>To do this, put the values in the equation. </h3>

-2 * 2 + 4 * 5 = -16

<h3>Solve</h3>

-4 + 20 = -16

<u>16 = -16</u>

<h2>(2,5) is not a solution of -2x+4y=-16</h2>

Hope this helps! :)

-Peredhel

Reptile [31]4 years ago
7 0
This is false when u fill in for x you get the answer -3 and it should be five and when you fill in for why you get the answer 18 and it should be 2 which makes the statement incorrect
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Answer: I got -2

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the answer is c i did the test

Step-by-step explanation:

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It is estimated % of all adults in United States invest in stocks and that % of U.S. adults have investments in fixed income ins
katovenus [111]

Complete question :

It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

Answer:

0.929 ; 0.306

Step-by-step explanation:

Using the information:

P(stock) = P(s) = 28% = 0.28

P(fixed income) = P(f) = 0.85

P(stock and fixed income) = p(SnF) = 26%

a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.

P(F|S) = p(FnS) / p(s)

= 0.26 / 0.28

= 0.9285

= 0.929

(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

P(s|f) = p(SnF) / p(f)

P(S|F) = 0.26 / 0.85 = 0.3058823

P(S¦F) = 0.306 (to 3 decimal places)

3 0
3 years ago
On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi
blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

{22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19}  + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069

I hope that works for you!

4 0
3 years ago
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