The answer to the question
Answer:
The answer to your question is it has no solution
Step-by-step explanation:
Inequality
16(t - 1) + 10 > 8(t + 2) + 4(t - 1) + 4t
-Expand
16t - 16 + 10 > 8t + 16 + 4t - 4 + 4t
- Group like terms
16t - 8t - 4t - 4t > 16 - 4 + 16 - 10
-Simplify
0 > 18
- It has no solution because the variable is cancelled.
The answer is 3.6. Hope this helps!
Answer:
Option 2 is right
Step-by-step explanation:
Given that

We can write this in polar form with modulus and radius

Hence angle = 60 degrees and

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360
Using Demoivre theorem we get 5th root would be
5th root of 2 multiplied by 1/5 th of 60, 420, 780,....
![z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\](https://tex.z-dn.net/?f=z%3D%20%5Csqrt%5B5%5D%7B2%7D%20%28cos12%2Bisin12%29%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos84%2Bisin84%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos156%2Bisin156%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos228%2Bisin228%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos300%2Bisin300%29%5C%5C)
Out of these only 2nd option suits our answer
Hence answer is Option 2.