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liraira [26]
3 years ago
10

Can someone pleaseeee help and if you’re correct i’ll give brainliest

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

Can you give me the website to see the problem or something.

Step-by-step explanation:

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Factor the expression and then evaluate without a calculator:
ivanzaharov [21]
The answer to the question

4 0
3 years ago
Solve 16(t - 1) + 10 > 8(t + 2) + 4(t - 1) + 4t.
Neporo4naja [7]

Answer:

The answer to your question is it has no solution

Step-by-step explanation:

Inequality

                   16(t - 1) + 10 > 8(t + 2) + 4(t - 1) + 4t

-Expand

                   16t - 16 + 10 > 8t + 16 + 4t - 4 + 4t

- Group like terms

                   16t - 8t - 4t - 4t > 16 - 4 + 16 - 10

-Simplify

                                       0 > 18

- It has no solution because the variable is cancelled.

3 0
3 years ago
Read 2 more answers
5 times what equals 18
cupoosta [38]

The answer is 3.6. Hope this helps!

5 0
4 years ago
Read 2 more answers
Which of the following is a solution of z^5 = 1 + √3 i?
nordsb [41]

Answer:

Option 2 is right

Step-by-step explanation:

Given that

z^5=1+\sqrt{3} i

We can write this in polar form with modulus and radius

|z^5|= \sqrt{1+3} =2\\tan of Angle t =\sqrt{3} \\

Hence angle = 60 degrees and

|z^5|= 2(cos60+isin60)

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\

Out of these only 2nd option suits our answer

Hence answer is Option 2.

8 0
3 years ago
James is given the diagram below and asked to prove that d is congruent to f. What would be the missing step of the proof? I onl
klemol [59]
The correct answer is B
3 0
3 years ago
Read 2 more answers
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