Answer:
980,100
Explanation:
let the recessive condition (aa) be represented as q² which is the genotypic frequency = 100/1,000,000 = 0.0001
allelic frequency of a = q = √q² = √0.0001 = 0.01. thus q = 0.01
From the formula p + q = 1 where p is the allelic frequency of A.
since q = 0.01
p = 1 - 0.01 = 0.99. The allelic frequency of A (p) = 0.99
p² = 0.99² = 0.9801. Genotypic frequency of AA= 0.9801
= 0.9801 x 1,000,000 = 980,100 individuals with AA (homozygous normal)
For 2pq genotypic frequency for hetrozygous (Aa).
Using the formula p² + 2pq + q² = 1. Since p² = 0.9801 and q² = 0.0001
2pq = 1 - (p² + q²)
= 1 - (0.9801 + 0.0001)
= 1 - (0.9802)
= 0.0198 = 0.0198 x 1,000,000 = 19,800 individuals with Aa
Answer:
Superficial Anatomy is most useful for <em><u>examining the outside features of the body</u></em>.
The principal-agent problem could be defined by saying that it is an agent who benefits from the effort of others without having even participated in the joint effort. It is a concept that is to be linked more broadly to the problems of information asymmetry.
<span>The term moral hazard refers to a type of market failure where the existence of insurance against a certain risk increases the likelihood of the occurrence of the event causing the risk.</span>
<u>The right answer is:</u>
Principal-agent problem matches with 2
Asymmetric information matches with 3
Adverse selection matches with 4
Moral hazard matches with 1
Answer:
The answer is C. Here is proof. It's correct trust me!!
Explanation:
