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Pani-rosa [81]
3 years ago
10

Need help with homework, I'm having a hard time understanding what to do.

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

i know what you can do

go to jupiter to get more stupider

Step-by-step explanation: #6 yr old burns

#ameture hour

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SOMEONE PLS HELP will mark brainliest
kogti [31]

Answer:

f(t)=-16t^2+8t+2

Step-by-step explanation:

Take the initial velocity(8)put in for vt. Then take height(2) and put in for s. giving you the equation. f(t)= -16t^2+8t+2

7 0
3 years ago
The no solution for 6-3+4x+1
Nataly_w [17]
Yes there is a solution for 6-3+4x+1 it is
4+4x because u add up all the like terms or variable
3 0
3 years ago
Read 2 more answers
Find the area of the blue sector. Use 3.14 for pi and round to the nearest hundredth.
jeka94

Answer:

Option C 25.64\ in^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

we have

r=7\ in

substitute

A=\pi(7)^{2}=49\pi\ in^{2}

Remember that

360 degrees subtends the complete area of the circle

so

by proportion

Find the area of the blue sector for an angle of 60 degrees

\frac{49\pi}{360}=\frac{x}{60}\\ \\x={49\pi*60/360

x=25.64\ in^{2}

3 0
3 years ago
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Round 35295 to the nearest thousand
Alex_Xolod [135]

35000, rounding down from five.

4 0
3 years ago
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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

5 0
2 years ago
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