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Svetach [21]
3 years ago
6

HELP WITH ONE MORE!!!!!!!!

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

f(x + 3) = (4x + 13)/(x - 3)

Step-by-step explanation:

If f(x) = (4x + 1)/(x - 6)

then in f(x + 3)...js replace x with (x + 3)...

f(x + 3) = (4(x + 3) + 1)/(x + 3 - 6)

;f(x + 3) = (4x + 13)/(x - 3)

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Find the exact values of x and r
NemiM [27]

Answer:

Below

Step-by-step explanation:

You can use sine law to solve this : sina / A = sinb / B

We will first find side x

We know that since this is a special triangle that side will = 28, but we can prove this mathematically :

sin(45) / 28 = sin(45) / x

= 28 sin(45) / sin(45)

x = 28

Now to find side r just use Pythagorean theorem a^2 + b^2 = c^2 :

c^2 = 28^2 + 28^2

      = 1568

Square root this number

r = 39.597

The just round to however your teacher wants

If you didn't already know about special triangles, an isosceles right triangle like this one has a ratio which is the two legs will equal each other, while the hypotenuse is √2a . You could have also used this to solve.

Hope this helps! Best of luck.  

3 0
3 years ago
Please help!
ladessa [460]
Area = length x width
the "big" rectangle: length = 15,  width = 14
the blue rectangle is: length = 15 - 4,  width = 14 - 6

Area of blue rectangle = (15 - 4)(14 - 6)
Answer: D
8 0
3 years ago
Read 2 more answers
A card is drawn from a 52-card deck. It the card is a picture card, we toss a coin. If the card is not a picture card, we roll a
emmainna [20.7K]
52/6 your answer is 5. 
3 0
3 years ago
The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension T T and inv
emmasim [6.3K]

Answer: T=40.96\ KgF

Step-by-step explanation:

We know that:

n: The number of vibrations per second of the nylon guitar string.

T: Tension.

L: The length of the string.

Since  n  varies directly with the square root of the  T and inversely with  L, the equation has the following form:

n=k*\frac{\sqrt{T} }{L}

Where "k" is the constant of variation.

Knowing that when n=15 and L=0.6, T=256, we can find the value of "k":

n=k*\frac{\sqrt{T} }{L}\\\\L*n=k\sqrt{T}\\\\\frac{L*n}{\sqrt{T}}=k\\\\k=\frac{(0.6)(15)}{\sqrt{256}}\\\\k=0.5625

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into n=k*\frac{\sqrt{T} }{L} and solve for T:

12=(0.5625)\frac{\sqrt{T} }{0.3}\\\\\frac{12(0.3)}{(0.5625)}=\sqrt{T}\\\\(6.4)^2=T\\\\T=40.96\ KgF

8 0
3 years ago
Please show me how you were able to get the answer :)
alex41 [277]
h(x)=\begin{cases}-x^2+4x-3\ \ \forall\ \  x\in [1,3]\\ 0 \ \text{other case} \end{cases}
8 0
3 years ago
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