All categories

3 years ago

18. [Algebra - Expansion] Expand 3(x + 2)

2 answers:

7 0

First you you distribute the 3 (3 times x and 3 times 2)
3x+6
Then divide 3x on both sides (3x divided by 3x and 6)
Your answer should be x=2

alexira [117]3 years ago

4 0

Answer:

Step-by-step explanation:

3(x + 2) = 3*x + 3*2

= 3x + 6

You might be interested in

10×(6×5) +9^3 ×8<br><img src="https://tex.z-dn.net/?f=10%20%5Ctimes%20%286%20%5Ctimes%205%29%20%2B%20%20%7B9%7D%5E%7B3%7D%20%20%

Minchanka [31]

Answer: 6132

Step-by-step explanation:

10x(6x5)+9^3 x8

10x30+9^3 x8

10x30+729x8

300+729x8

300+5832

6132

Hope this helps!

3 0

3 years ago

Round 7.21 divided by 7 to the nearest tenth

tensa zangetsu [6.8K]

1 is the answer.

The exact answer is 1.03, but we have to round it to the nearest tenth which is 0 because 3 is less than 5.

8 0

2 years ago

In order to solve for the variable in the equation 2 (4 x + 3) + 4 = 3 x minus (2 x + 4), Giovanni first applies the distributiv

Alenkinab [10]

Answer:

8x + 6 + 4 = 3x - (2x + 4)

Step-by-step explanation:

When Gio applies the distributive property, the equation above is the result. Naturally, I look at the 1st parenthesis I see and start the 1st distributive property there first. The 2nd distributive property would be the other parenthesis where you multiply by -1, so you would get 8x + 6 + 4 = 3x - 2x - 4

5 0

2 years ago

Read 2 more answers

Nata [24]

Answer: 15, -8

Step-by-step explanation:

$u_2=7\\u_2=u_1+r\\u_3=u_1+2r\\u_4=u_1+3r\\\\u_1+u_2+u_3+u_4=4u_1+6r=12\\u_1+r=7\\\\$

$\left \{ \begin {array} {ccc|c|c}u_1+r&=&7&-4&-6\\4u_1+6r&=&12&1&1\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}2r&=&-16\\-2u_1&=&-30\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}r&=&-8\\u_1&=&15\\\end {array} \right.\\\\\\Proof:\\u_1=15\\u_2=7\\u_3=-1\\u_4=-9\\sum=12\\$

6 0

2 years ago

What is 8x8??..........

dlinn [17]

Answer:

is the answer please mark me brainlest

4 0

2 years ago

Read 2 more answers