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fgiga [73]
3 years ago
9

18. [Algebra - Expansion] Expand 3(x + 2)

Mathematics
2 answers:
stepan [7]3 years ago
7 0
First you you distribute the 3 (3 times x and 3 times 2)
3x+6
Then divide 3x on both sides (3x divided by 3x and 6)
Your answer should be x=2
alexira [117]3 years ago
4 0

Answer:

Step-by-step explanation:

3(x + 2) = 3*x + 3*2

= 3x + 6

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3500∙(−2)∙(−5)
xeze [42]
3500*10= 35,000 the answer to the question
8 0
3 years ago
Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 i
vivado [14]
No more than 74 on average of 5 games means no more than 370 shots on total. If you add all of the numbers up you will get 292, so he can still shoot 370-292=78 in the last round, which is answer choice B.
5 0
3 years ago
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Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
2 years ago
Simplify 3ab + 4ab + 5
Anettt [7]
<span>Simplify 3ab + 4ab + 5
= 7ab + 5 (combine like terms)

hope it helps</span>
5 0
3 years ago
Read 2 more answers
Find the y intercept.
vovangra [49]

Answer: Table= 4

Graph= 15

Step-by-step explanation:

If you look at the table it will interest y at 4 because x is zero there. And in the graph you can see that the line will interest the y axis at 15.

7 0
3 years ago
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