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Ymorist [56]
3 years ago
15

Help me please i’ll rate brainliest

Mathematics
1 answer:
Cloud [144]3 years ago
5 0

Answer:

<em>- 1.568</em>  

Step-by-step explanation:

Let's assume that the base of the given logarithm is 10.

log m = 0.345 ⇒ 10^{0.345} = m

log n = 1.223 ⇒ 10^{1.223} = n

mn = 10^{0.345} × 10^{1.223} = 10^{1.568}

\frac{1}{mn} = 10^{-1.568}

log 10^{-1.568} = - 1.568 × log 10 = <em>- 1.568</em>

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From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

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<u>Again </u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

As amount is double its principal

So, A = 2 × $1000 = $2000

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So, The time period to get account double is 14 years 26 days

Hence From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days . Answer

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