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sdas [7]
3 years ago
6

Solve for x please help me

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

4

Step-by-step explanation:

By intersecting chords theorem:

12x = 3(x + 12) \\  \\ 12x = 3x + 36 \\  \\ 12x - 3x = 36 \\  \\ 9x = 36 \\  \\ x =  \frac{36}{9}  \\  \\ x = 4

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I hope this helps

Answer is 5H+4=A
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Which undefined term can contain parallel lines?<br> O line<br> O plane<br> o point<br> O ray
lapo4ka [179]

Answer:

should be a plane.

a plane is two dimensional and has intimate length and width. so it contains infinite lines.

4 0
3 years ago
PLEASE HELP!! Trevor is writing a paper that must be 50,000 words long. He had already written 23,210 words. Write an inequality
almond37 [142]

Answer:

50,000 ≤ 23,210 + 5x

x = Average number of words per week

Step-by-step explanation:

Start off with 50,000 because that's how many words the paper needs to have.

Use "≤" because Trevor needs to write at least 50,000 words. (He can write more).

Trevor already wrote 23,210 words plus x words per week for 5 weeks.

(Solving for x will help you find the average number of words Trevor must write per week for 5 weeks).

5 0
3 years ago
ONLY SERIOUS ANSWERS!!!! 25 POINTS
AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

16x²-169x²+88x+416x+265-400 = 0

-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504±\sqrt{504^{2}-4(-153)(-135) })/2(-153)

x=(-504±\sqrt{254016-82620 })/-306

x=(-504±\sqrt{171396})/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

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3 years ago
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45 or a random number lol just put in 45 and see if it orks
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