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lesantik [10]
4 years ago
7

Teacher chooses to students in a class of 15 girls and 10 boys the students are randomly choosing what is the probability that t

he teacher chooses to girls
Mathematics
1 answer:
Vadim26 [7]4 years ago
4 0

Answer:

7/20

Step-by-step explanation:

So first we know that there are a total od 25 students

15+10=25

And the probability of choosing the first girl is 15/25 or 3/5 simpler terms.

Now to be able to choose another girl in a row just multiply the then probability

So we started off with 25, if a girl was choosen, the population would b 24

and with 24, there is a missing girl so instead of 15 it is 14

now 14/24 or 7/12 simplified

multiply the two

7/12*3/5=21/60

Simplified

7/20

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(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
4 years ago
i have 811 handkerchief in all,and need 25 for one quilt. How many quilts can I make and how many handkerchief will be left over
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