Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that
For parts (a) and (b), you're given everything you need to determine
.
For part (c), if
and
are mutually exclusive, then
, so
. If the given probability is
, then you can find
. But if this given probability is for the intersection, finding
is impossible.
For part (d), if
and
are independent, then
.
The answer is: [A]: "right [triangle]" .
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Explanation:
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Given: Side lengths:
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" <span>24 in., 32 in., and 40 in " ;
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Divide each side length by "8" ;
</span><span>
24 in. / 8 = 3 in. ;
32 in. / 8 = 4 in. ; and
40 in. / 8 = 5 in. .
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3 in . , 4, in, 5 in. ; is a "right triangle" ;
since: 3</span>² + 4² = 5² ;
→ 9 + 16 = 25 ;
according to the Pythagorean theorem: " a² + b² = c² " .
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The product of this is 81
Answer:
y=-3x-14
Step-by-step explanation:
y=mx +c
m= 1/3
perp m= -3
goes through point (6,-4)
sub numbers
Answer:
66%
Step-by-step explanation:
- First, add 20 + 10 = 30. This will give you the total amount of games.
- Now, make this into a fraction for won games. This should be 20/30.
- Next, take 20/30 and simplify it. You should get 2/3 as a fraction.
- Now, take 2 and divide by 3. (2/3) You should get .66 repeating. This is equal to 66%.
- Therefore 66% is the answer.
- Hope this helps! If you need a further explanation please let me know.
