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2 years ago

A shirt originally cost $39.39, but it is on sale for $27.57. What is the percentage decrease of the price of the shirt?

Mathematics

1 answer:

IgorLugansk [536]2 years ago

3 0

30 percent decrease

Step-by-step explanation:

looking at this i know its a percent decrease

so how do we find percent decrease ?

first we subtract the first value 39.39 & the final value 27.57

39.39-27.57 = 11.82

then we divide 11.82 by the first value

like this 11.82÷39.39 = 0.3000

then we multiply what we got by 100

0.3000×100= 30 percent

the way that most people mess up is when they divide sometimes they might do 39.39 divided by 11.82 instead of 11.82÷39.39.

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mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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