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mihalych1998 [28]
3 years ago
15

(-1)^(n+1) + (-1)^n-1)=?

Mathematics
2 answers:
stepan [7]3 years ago
8 0
Hello,

(-1)^{n+1} + (-1)^{n-1} = (-1)^{n-1} ((-1)^2+1)= 2*(-1)^{n-1}
Jlenok [28]3 years ago
8 0
(-1)^{n+1}+(-1)^{n-1}=(-1)^n\cdot(-1)^1+(-1)^n\cdot(-1)^{-1}\\\\=(-1)^n\cdot(-1)+(-1)^n\cdot(-1)=-(-1)^n+[-(-1)^n]\\\\=\boxed{-2(-1)^n}
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