Answer:
2,3,6
Step-by-step explanation:
5,226 ...(1)
unit digit=6
6 is divisible by 2,
so (1) is divisible by 2.
last two digits=26 ,not divisible by 4,
so (1) is not divisible by 4.
5+2+2+6=15 divisible by 3 but not divisible by 9.
so (1) is divisible by 3 but not divisible by 9.
2×3=6,so (1) is divisible by 6.
unit digit=6≠0 or 5
so (1) is not divisible by 5 or 10.
Hello
<span>3 2/3 \ 3 2/9
(32/3) × (9/32) = 9/3=3</span>
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
Answer:
10 miles if im not wrong
Step-by-step explanation:
