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tino4ka555 [31]
3 years ago
14

How do i solve 1.6 = d/3

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
D=4.8 hope this helps
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Please, someone help me. 3/4x-7=8
Cloud [144]

Answer:

x= 20

Step-by-step explanation:


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What is (5 7/8 minus 6 3/4) minus 2 1/4 ? Please give me the correct answer and stepy by step instructions.
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(5 7/8-6 3/4)-2 1/4
Solve the numbers in the parenthesis ( I change the denominators to a common denominator that 8 and 4 share)
(5 7/8 - 6 3/4)-2 1/4
          ^
        -1  1/8-2 1/4
(I use KKC aka Keep Change Change where I keep -1  1/8 the same, change the minus sign to a plus sign, and change the -2 1/4 to positive) ( I change the denominators to a common denominator that 8 and 4 share)
-1  1/8 + +2 1/4 = 1  1/8 
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the beta club is raising money to buy bags of food to donate to a local animal shelter. A bag of cat food cost 12$. If they rais
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8 0
3 years ago
What is half of seven in a whole number
Nikitich [7]
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6 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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