Given:
To find:
The value of f'(x).
Solution:
Formulae used:
Chain rule:
![\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
Where C is an arbitrary constant.
We have,
Differentiate with respect to x.
Therefore, the required values is .
Answer:
The area is 0.002m² to 3 dp
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes(I.e cross sectional area of pipe ) , this time the a circle.
It requires us to look for the area of the shape
Given data
Diameter d = 5cm
Converting to mm = 5/100= 0.05m
Radius of circle r=d/2=0.05/2 =0.025mm
Given the area of the circle
A=πr²
A=3.14*0.025²
A=0.0019m²
To 3 dp we have area as 0.002m²
32 (forwards) /16 (team's) =2 forwards on each team 80 (gaurds) / 16 (team's) =5 gaurds on each team
