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1 year ago

Which situation is modeled by the graph? PLEASE HELP!

Mathematics

2 answers:

marta [7]1 year ago

8 0

Answer:

Height of jump rope used over time.

Step-by-step explanation:The Height is stable and even so not an elevator as it goes to multiple floors not just one and is not used frequently after the same amount of time.Not the rest for the same reason.Jump rope as it can be uniform in height and time unlike the rest.

spin [16.1K]1 year ago

8 0

I believe it’s the first one

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A flower box in the shape of a right rectangular prism is made of thin metal, shown below. The box has length 90 centimeters (cm

masya89 [10]

1) Volume of the box = 90*45*45=182250 cm³
2) filled with soil = 0.85*182250= 154912.5 cm³
3) 182250 cm³-154912.5 cm³=27337.5 cm³ not filled
4) 27337.5 cm³/28316 cm³=0.9654 ≈ 1 bag

4 0

2 years ago

Combine the like terms to create an equivalent expression 4z- (-3z)

NNADVOKAT [17]

Answer:

Step-by-step explanation:

subtracting a negative is like adding

$4z - (-3z)\\4z+3z\\7z$

4 0

2 years ago

Someone please help today is the last day for missing work

Anit [1.1K]

Answer:

Domain: 10, 1, 2

Range: 3, 4, 9, 5

Domain is the x values

Range is the y values

8 0

3 years ago

Rewrite the radical exponent as a radical

shepuryov [24]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
\left( 5^{\frac{3}{4}} \right)^{\frac{2}{3}}\implies 5^{\frac{3}{4}\cdot \frac{2}{3}}\implies 5^{\frac{1}{2}}\implies \sqrt[2]{5^1}\implies \sqrt{5}$

3 0

2 years ago

Clara created a coordinate grid of her city. The bowling alley is located at (10, 12) and the skating rink is located at (-6, -4

yulyashka [42]

First we need to know the coordinates of the movie theater, we can do this applying the midpoint formula:

$\begin{gathered} P(BA,SR)=(\frac{10-6}{2},\frac{12-4}{2})\text{ = (}\frac{4}{2},\frac{8}{2}) \\ \Rightarrow P(BA,SR)=(2,4) \end{gathered}$

We have that the movie theater is located at (2,4). Now we use this coordinates to find the location of Clara's house using again the midpoint formula:

$\begin{gathered} P(MT,SR)=(\frac{-6+2}{2},\frac{4-4}{2})=(-\frac{4}{2},0) \\ \Rightarrow P(MT,SR)=(-2,0) \end{gathered}$

Therefore, Clara's house is located at (-2,0)

6 0

10 months ago