Find the area of the circle with a circumference of 30(pie). Write your solution in terms of (pie)
1 answer:
You might be interested in
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
<h3>x = 21/5</h3>
Step-by-step explanation:
<h3>___________________________</h3><h3>Given →</h3>5x:9 = 7:3
<h3>So,</h3>→ 5x/9 = 7/3
→ x = (7 × 9)/(3 × 5)
→ x = 21/5
<h3>___________________________</h3><h3>Hope it helps you!!</h3>