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WINSTONCH [101]
3 years ago
6

Can someone please answer this with step please.

Mathematics
2 answers:
Tems11 [23]3 years ago
5 0

Answer:

It is the sedond one

Step-by-step explanation:

svlad2 [7]3 years ago
4 0

7n, 4n because they have the same variable, n.

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Is x2 - 2 a factor of x4 - 2x3 + 3x2 - 4x + 5 ?
SashulF [63]
Yes it x2 is a factor because at some point and time 2x would cross 4x
6 0
4 years ago
Solve t-v/r=k, for v
Arisa [49]

Answer:

t-v/r = k

t-k = v/r

v = r(t-k)

Hope this helps!

6 0
3 years ago
Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)
dsp73

Answer:

a) \log 52

b) \log_57

Step-by-step explanation:

Use logarithm properties:

\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}

Then

a) \log 13+\log 4=\log 13\cdot 4=\log 52

b) \log_514-\log _52=\log _5\dfrac{14}{2}=\log _57

7 0
4 years ago
Which ratio shown below is NOT equivalent to − 15 23
Talja [164]

Answer:

what is the answer below

Step-by-step explanation:

4 0
4 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
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