All categories

3 years ago

Help plz I don’t get it

Mathematics

2 answers:

AleksandrR [38]3 years ago

8 0

1-a-1 13
1-b-1 2 3 5 6 10 15 30

laila [671]3 years ago

3 0

(I will do the first two parts of each question)

1a. 13 is only divisible by 1 and 13, so they are its factors.

1b. 30 can be divided by 1 and 30, and 2*15=30, 3*10=30, and 5*6=30, so 30's factors are 1, 2, 3, 5, 6, 10, 15, and 30.

2. 75's factors are: 1, 3, 5, 15, 25, and 75. So, there can be 75 piles of 1, 25 piles of 3, 15 piles of 5, etc. (3 more)

3a. 3*1=3, 3*2=6, 3*3=9, etc. so the first 5 multiples of 3 are: 3, 6, 9, 12, 15

3b. Same as before, so: 10, 20, 30, 40, 50

You might be interested in

What is the euclidean distance between x(3,2,5) and y(2,3,3) in three dimensional space?

Likurg_2 [28]

Answer:

b) 2.45

Step-by-step explanation:

The Euclidean distance in 3-space is the root of the sum of the squares of the x-, y-, and z-differences between the points.

<h3>Application</h3>

For the given points ...

$x(3,2,5)=(x_1,y_1,z_1)\quad\textsf{and}\quad y(2,3,3)=(x_2,y_2,z_2)$

The distance between x and y is ...

$d=\sqrt{(x_2-x_1)^2+(y_2=y_1)^2+(z_2-z_1)^2}\\\\d=\sqrt{(2-3)^2+(3-2)^2+(3-5)^2}=\sqrt{1+1+4}\\\\d=\sqrt{6}\approx2.45$

5 0

2 years ago

An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

sattari [20]

They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:

y=150-600t x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)

7 0

3 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

4 0

3 years ago

Solve for x or find x

Vanyuwa [196]

Answer:

x = 7

Step-by-step explanation:

Assuming the quadrilateral is a parallelogram, then the diagonals bisect each other.

7x - 8 = 41

7x = 49

x = 7

7 0

2 years ago

Read 2 more answers

What is the gcf of 3/7 and 4/9?

LiRa [457]

Answer:

1/63

Step-by-step explanation:

There are a couple of ways to do this.

Look for the GCF of the numerators when a common denominator is used.

GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

GCF(3/7, 4/9) = 1/63

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

(4/9)/(3/7) = 1 remainder 1/63*

(3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

_____

<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

3 0

2 years ago