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dmitriy555 [2]
3 years ago
11

Help plz I don’t get it

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0
1-a-1 13
1-b-1 2 3 5 6 10 15 30
laila [671]3 years ago
3 0

(I will do the first two parts of each question)

1a. 13 is only divisible by 1 and 13, so they are its factors.

1b. 30 can be divided by 1 and 30, and 2*15=30, 3*10=30, and 5*6=30, so 30's factors are 1, 2, 3, 5, 6, 10, 15, and 30.

2. 75's factors are: 1, 3, 5, 15, 25, and 75. So, there can be 75 piles of 1, 25 piles of 3, 15 piles of 5, etc. (3 more)

3a. 3*1=3, 3*2=6, 3*3=9, etc. so the first 5 multiples of 3 are: 3, 6, 9, 12, 15

3b. Same as before, so: 10, 20, 30, 40, 50

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A

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2 years ago
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2 years ago
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5 0
3 years ago
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Find one counter example to show that the conjecture is false. angle 1 and angle 2 are​ supplementary, so one of the angles is a
Mrac [35]

Answer:

B. m ∠ 1 = 90° and m ∠ 2 = 90°

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4 0
3 years ago
5x2/11. how do i find simplest form
adelina 88 [10]
Assuming you are multiplying 5 times 2/11 then you just put 5/1 because anything divided by 1 is still one, and then multiply 5/1 by 2/11. Meaning, 5 times 2 is 10. And 1 times 11 is 11. So it would be 2/11. You multiply the numerators(top number) and denominators(bottom number). 2/11 is already simplified
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3 years ago
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