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morpeh [17]
2 years ago
12

Which expression results in a sum or difference of five and six fifty fourths? (3 points) a eight and seven ninths minus three a

nd four sixths b six and eight ninths minus one and five sixths c four and one sixths plus one and one ninth d three and three sixths plus two and four ninths
Mathematics
1 answer:
Genrish500 [490]2 years ago
6 0

Answer:

a)  eight and seven ninths minus three and four sixths

Step-by-step explanation:

The required result is 5\frac{6}{54}

a)

8\frac{7}{9} -3\frac{4}{6}\\\\=\frac{79}{9}  -\frac{22}{6} \\\\Simplifying\ the\ expression:\\\\=\frac{474-198}{54} \\\\=\frac{276}{54}\\\\=5\frac{6}{54}

b)

6\frac{8}{9} -1\frac{5}{6}\\\\=\frac{62}{9}  -\frac{11}{6} \\\\Simplifying\ the\ expression:\\\\=\frac{372-99}{54} \\\\=\frac{273}{54}\\\\=5\frac{3}{54}

c)

4\frac{1}{6} +1\frac{1}{9}\\\\=\frac{10}{9}  +\frac{25}{6} \\\\Simplifying\ the\ expression:\\\\=\frac{60+225}{54} \\\\=\frac{285}{54}\\\\=5\frac{15 }{54}

d)

3\frac{3}{6} +2\frac{4}{9}\\\\=\frac{22}{9}  +\frac{21}{6} \\\\Simplifying\ the\ expression:\\\\=\frac{132+189}{54} \\\\=\frac{321}{54}\\\\=5\frac{51 }{54}

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andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

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A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

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P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

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