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mariarad [96]
2 years ago
13

One year Perry had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male pitch

er at his​ school, with an ERA of 3.02. ​Also, Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the​ males, the mean ERA was 4.206 and the standard deviation was 0.846. For the​ females, the mean ERA was 4.519 and the standard deviation was 0.789. Find their respective​ z-scores. Which player had the better year relative to their​ peers, Perry or Alice​
Mathematics
1 answer:
Blizzard [7]2 years ago
7 0

Answer:

z score Perry z=-1.402

z score Alice z=-1.722

Alice had better year in comparison with Perry.

Step-by-step explanation:

Consider the provided information.

One year Perry had the lowest ERA​ of any male pitcher at his​ school, with an ERA of 3.02. For the​ males, the mean ERA was 4.206 and the standard deviation was 0.846.

To find z score use the formula.

z=\frac{x-\mu}{\sigma}

Here μ=4.206 and σ=0.846

z=\frac{3.02-4.206}{0.846}

z=\frac{-1.186}{0.846}

z=-1.402

Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the​ females, the mean ERA was 4.519 and the standard deviation was 0.789.

Find the z score

where μ=4.519 and σ=0.789

z=\frac{3.16-4.519 }{0.789}

z=\frac{-1.359}{0.789}

z=-1.722

The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.

It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.

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Example 6
lapo4ka [179]

Answer:

The answer is below

Step-by-step explanation:

1. COST Mr. Rivera wants to purchase a riding lawn mower, which is on sale for 15% off the marked price.  The store charges sales tax 6.5% on all sales. Write a  function p(x) that represents the price after a 15%  discount. Write a function t(x) that represents the total  cost with sales tax. Write a composition of functions that  represents the total cost of a riding lawn mower on sale.  How much will Mr. Rivera pay for a riding lawn mower  that has a marked price of $3000?

Solution:

a) Let x represent the marked price and p(x) represent the price after discount. Since a discount of 15% is given, the price would be:

p(x) = x(100\% -15\%)=x(1-\frac{0.15}{100} )=0.85x

b) If x = discounted price and t(x) = total  cost with sales tax, then:

t(x) = x(100\% +6.5\%)=x(1+\frac{6.5}{100} )=1.065 x

c) Let t(x) represents the total  cost with sales tax

t[p(x)] =p(x)+6.5\%\ of\ p(x) \\\\t[p(x)] = 0.85x+(0.065*0.85x)\\\\t[p(x)] =0.90525x\\\\for\ x=\$3000:\\\\t[p(3000)] = 0.90525*3000=\$2715.75

8 0
3 years ago
I NEED HELP FASTTT D:
Doss [256]

Answer:

12x + 15 = 12x - 15

Step-by-step explanation:

-5x - 25 = 5x + 25

-25 = 10x + 25

-50 = 10x

-5 = x

12x + 15 = 12x - 15

15 = -15  ( No solution )

12x + 15 = 3(4x + 5)

12x + 15 = 12x + 15

12x = 12x

0 = 0  ( True for all x's )

7x + 21 = 21

7x = 0

x = 0

4 0
2 years ago
HELLPPP PLEASE WILL GIVE BRAINLIEST ​
avanturin [10]

Answer:

25

Step-by-step explanation:

90-65=25

4 0
3 years ago
Can u help me with my workk
eimsori [14]
You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)
6 0
2 years ago
8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components
Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

V(X) = np(1 - p)

In this problem:

  • 95% pass final inspection, hence p = 0.95
  • 120 components are inspected in one day, hence n = 120.

The variance is given by:

V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

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2 years ago
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