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Contact [7]
3 years ago
6

What number does the model show? 600 hundred 14 Tens 2 ones

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

742

Step-by-step explanation:

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What is 2% of 33 give the ANSWER
marysya [2.9K]

Answer:

0.66

Step-by-step explanation:

33 * 0.02 = 0.66

6 0
3 years ago
Read 2 more answers
Not sure how I would solve this
suter [353]
<h3>Answers:</h3>

The first ordered pair is   ( -4 , -3 )

The second ordered pair is   ( 8, 3 )

=================================================

Explanation:

The first point is (x,-3) where x is unknown. It pairs up with y = -3 so we can use algebra to find x

x-2y = 2

x-2(-3) = 2 ... replace every y with -3; isolate x

x+6 = 2

x = 2-6

x = -4

The first point is (-4, -3)

---------------------------

We'll do something similar for the other point. This time we know x but don't know y. Plug x = 8 into the equation and solve for y

x-2y = 2

8-2y = 2

-2y = 2-8

-2y = -6

y = -6/(-2)

y = 3

The second point is (8, 3)

4 0
3 years ago
Rationalize 1 plus root 2 divided by 1 minus root 2
yulyashka [42]
The rationalized form of 1+ √2/1-√2 is -2√2-3

6 0
3 years ago
Can you tell me the ones I got wrong and which are the correct ones. Might need to zoom in. Will give brainly
Mama L [17]

Answer:

I think

Step-by-step explanation:

y might be 50 degrees

z might be 40 degrees

w might be 140 degrees

x might be 130 degrees

7 0
3 years ago
Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
3 years ago
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