Based on the above:
The slope of P'Q' is = -3/2
The length of P'Q' is approximately = ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
<h3>What is the polygon about?</h3>
The slope of P'Q'
= -6/4 = -3/2
The length of P'Q' =
P'Q' = 
= 
= ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
Therefore;
P'Q' =
P'Q' =
x ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
= ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
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Hmm idk hard one jnmmdmkrkror
Answer:
the width would be 4 inches and the length would be 6 inches
Answer:
76.
Step-by-step explanation:
It is given that N is a 2-digit number.
Last two digits of N^2 is the same as N.
We know that, a number is even if it ends with 0,2,4,6,8.
If 0 is in end then we get two zeros in the square of that number.
It is clear that, number should ends with 6 to get the same number at the end.
It is clear that last two digits of (76)^2 is the same as 76.
Therefore, the required number is 76.