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hjlf
2 years ago
15

Polygon PQRS, shown in the figure, is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in p

olygon P'Q'R'S'. A polygon PQRS is plotted on a coordinate plane. The vertices P is at (10, 8), Q is at (6, 14), R is at (11, 16), and (15, 10). The slope of P'Q' is -1.5 . The length of P'Q' is approximately 5.39 .
Mathematics
1 answer:
nata0808 [166]2 years ago
7 0

Based on the above:

The slope of P'Q'  is = -3/2

The length of  P'Q' is approximately = \sqrt[3]{13}

<h3>What is the polygon about?</h3>

The slope of P'Q'

=  -6/4 = -3/2

The length of  P'Q' =

 P'Q' = \sqrt{6^2 + 4^2}

= \sqrt{52}

= \sqrt[2]{13}

Therefore;

P'Q' = \frac{3}{2}

 P'Q' =    \frac{3}{2}  x \sqrt[2]{13}

= \sqrt[3]{13}

Learn more about polygon from

brainly.com/question/1592456

#SPJ1

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Well 144 divided by 8
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3 years ago
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You drop a ball from a height of 0.5 meters. Each curved path has 52% of the height of the previous path. a. Write a rule for th
Verizon [17]

Answer:

a) a_n = 50 (0.52) ^ {n-1}

b) a_6 = 50 (0.52) ^ 5 = 1.90\ cm

Step-by-step explanation:

If each curved path has 52% of the previous height this means that \frac{a_{n+1}}{a_n} = 0.52

Then the radius of convergence is 0.52 and this is a geometric series.

The geometric series have the form:

a_n = a_1 (r) ^ {n-1}

Where

a_1 is the first term of the series and r is the radius of convergence.

In this problem

a_1 = 0.5 meters = 50 cm

r = 0.52

a) Then the rule for the sequence is:

a_n = 50 (0.52) ^ {n-1}

b) we must calculate a_6

a_6 = 50 (0.52) ^ 6-1\\\\a_6 = 50 (0.52) ^ 5 = 1.90\ cm

3 0
3 years ago
I tested positive for covid yesterday so i have no motivation to do this problem. Please don’t be slow when answering, I am ever
SOVA2 [1]

The value of  sector KL is 52

If JM and KN are two diamters of the circle,

then they intersect at the center

The sector JK and NM are equal

Thus,

The sector JN and KM are also equal

sector KM = sector KL + sector LM

Sector JN = Sector KM

sector JN = sector KL + sector LM

125 =  6x + 4 + 8x + 9

125 = 14x + 13

14x = 125 - 13

14x = 112

x = 8

sector KL = 6x + 4

= 6(8) + 4 = 48 + 4 = 52

Therefore, the sector KL is 52

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5 0
2 years ago
Which of these are qualdrilateral
Sholpan [36]

Answer:

any four sided closed shape

Step-by-step explanation:

can you add the option?

7 0
3 years ago
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What is the diameter of the following?
Tamiku [17]

Answer:

12

Step-by-step explanation:

The equation of a circle in standard form is

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where (h, k) are the coordinates of the centre and r is the radius

(x - 9)² + (y - 4)² = 36 ← is in standard form

with r² = 36 ⇒ r = \sqrt{36} = 6

diameter = 2 × r = 2 × 6 = 12

4 0
3 years ago
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