Question

Polygon PQRS, shown in the figure, is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in polygon P'Q'R'S'. A polygon PQRS is plotted on a coordinate plane. The vertices P is at (10, 8), Q is at (6, 14), R is at (11, 16), and (15, 10). The slope of P'Q' is -1.5 . The length of P'Q' is approximately 5.39 .

Answer 1

Based on the above:

The slope of P'Q'  is = -3/2

The length of  P'Q' is approximately = $\sqrt[3]{13}$

What is the polygon about?

The slope of P'Q'

=  -6/4 = -3/2

The length of  P'Q' =

 P'Q' = $\sqrt{6^2 + 4^2}$

= $\sqrt{52}$

= $\sqrt[2]{13}$

Therefore;

P'Q' = $\frac{3}{2}$

 P'Q' =    $\frac{3}{2}$  x $\sqrt[2]{13}$

= $\sqrt[3]{13}$

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