Answer:
why you color out the first part? what exctly is the question?
Step-by-step explanation:
Answer:
C. The answer is not correct. The student did not compute the sums of the horizontal and vertical directions correctly.
Answer:
serch it on google
Step-by-step explanation:
go to google
type in your question or the promblems
write the answer down
ANSWER
24
EXPLANATION
For a matrix A of order n×n, the cofactor
of element
is defined to be

is the minor of element
equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.
Here, we have

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

Since the determinant of a 2×2 matrix is

it follows that

so 
We are given the two functions

and

. Since the question is asking us for the value of x when f(x) is equal to g(x), all we need to do is equate the respective expressions together. This is what the result should be:

Now, just solve for x. If you want to save some time, you can use logic and then algebra. To do this, look at the square root. We cannot have an imaginary number, so we can rule out the first two options. Now, we are left with x = 2 and x = 4. When we plug in each x-value to the equation, only 4 works out with a result of 0.5 = 0.5. Therefore, the solution to f(x) = g(x) is
D) x = 4. Hope this helps and have a great day!