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3 years ago

X(2x-5)+x(2x-3)=(4x+6)(x-3)

Mathematics

2 answers:

Trava [24]3 years ago

8 0

Answer X=9

9( 18 -5) + 9( 18 -3)= (36 +6)(6)

117 135 = 252

252=252

Helga [31]3 years ago

4 0

Answer:

x=9

Step-by-step explanation:

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By rounding to 1 significant figure, estimate 6.4 x 7.35

densk [106]

Answer:

6.4 x 7.4 =47.36

Step-by-step explanation:

7.35 rounded will be 7.4

5 0

3 years ago

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Community Gym charges a $50 membership fee and a $60 monthly fee. Workout Gym charges a $180 membership fee and a $50 monthly fe

Vladimir79 [104]

Answer:

After 13 months the amount paid to both will be $830.

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

Given circle and circle with radii of 6cm and 4cm respectively.

noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

$\angle EAF = \theta = 140^\circ$

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

= 14.653 cm

In circle C

$\angle GCH = \theta = 140^\circ$

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

= 9.769 cm

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is 1.5 times the length of GH

i.e. 14.653 = 1.5 x 9.769

14.653 = 14.653

Hence proved.

6 0

3 years ago

An isosceles trapezoid has base angles 45 and bases of lengths 9 and 15 the area pf the trapezoid is

Nadusha1986 [10]

Tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3

Trapezoid area = ((sum of the bases) ÷ 2) • height

Trapezoid area = (9 + 15) /2 * height

Trapezoid area = 12 * 3

Trapezoid area = 36

7 0

3 years ago