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3 years ago

AREA OF A CIRCLE PLS HELP

Mathematics

2 answers:

sweet [91]3 years ago

8 0

Answer:

153.86 ft²

Step-by-step explanation:

Area = $\pi r^2$

= 3.14 * 7 * 7

= 153.86 ft²

Scilla [17]3 years ago

3 0

Answer:

if A =3.14*r^2 then the answer would be either 153.86

Step-by-step explanation:

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Sarah needs to cover a triangle that has a base of 3¼ inches and a height of 5½ inches. What is the area that Sarah needs to cov

eimsori [14]

Answer:

8 and 15/16 or 143/16

Step-by-step explanation:

3.25 * 5.5 = 17.875/2

7 0

3 years ago

An object that weighs 24 pounds on Mercury weighs approximately 80 pounds on Earth. A rock weighs 240 pounds on Mercury. What is

AnnyKZ [126]

Answer:

800 pounds.

Step-by-step explanation:

We have been given that an object that weighs 24 pounds on Mercury weighs approximately 80 pounds on Earth. A rock weighs 240 pounds on Mercury. We are asked to find the weight of rock on Earth.

We will use proportions to solve our given problem as proportions state that the ratio between two proportional quantities is equal.

$\frac{\text{Weight on Earth}}{\text{Weight on Mercury}}=\frac{80}{24}$

Upon substituting our given value, we will get:

$\frac{\text{Weight on Earth}}{240}=\frac{80}{24}$

$\frac{\text{Weight on Earth}}{240}\cdot 240=\frac{80}{24}\cdot 240$

$\text{Weight on Earth}}=\frac{80}{1}\cdot 10$

$\text{Weight on Earth}=800$

Therefore, the weight of rock on Earth would be approximately 800 pounds.

4 0

3 years ago

Solve for X and Y please

Alona [7]

See attached picture

5 0

3 years ago

The diagonals of a Rhombus are 2Dm and 3M. What’s is the area of the Rhombus??

NemiM [27]

Answer:

336 $m^{2}$

Step-by-step explanation:

Area of Rhombus = (1/2)*xy

Where x and y are length of diagonals

Area = (1/2) * 21 * 32 = 21* 16 = 336

Area = 336 m²

7 0

4 years ago

I need help on 4 and 6 please help me. Don’t put a link.

Arte-miy333 [17]

Answer:

I don't know about 4 but of no. 6, it is A

Step-by-step explanation:

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3 years ago

AREA OF A CIRCLE PLS HELP​

AREA OF A CIRCLE PLS HELP