Question

The equation of line WX is y = −2x − 5. Write an equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, 1).
y = 1 over 2 x − 3 over 2
y = − 1 over 2 x − 3 over 2
y = 1 over 2 x + 3 over 2
y = negative 1 over 2 x + 3 over 2

Answer 1

Answer:

third option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 5 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$ , then

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (- 1, 1) into the partial equation

1 = - $\frac{1}{2}$ + c ⇒ c = 1 + $\frac{1}{2}$ = $\frac{3}{2}$

y = $\frac{1}{2}$ x + $\frac{3}{2}$ ← equation of perpendicular line