Answer:
Clock on the satellite is slower than the one present on the earth = 29.376 s
Given:
Distance of satellite from the surface, d = 250 km
Explanation:
Here, the satellite orbits the earth in circular motion, thus the necessary centripetal force is provided by the gravitation force and is given by:
where
v = velocity of the satellite
R = radius of the earth = 6350 km = 6350000 m
G = gravitational constant =
M = mass of earth =
Therefore, the above eqn can be written as:
Now, for relativistic effects:
Now,
r = R + 250
Ratio of rate of satellite clock to surface clock:
Clock on the satellite is slower than the one present on the earth: