We want to see if the first selection is dependent on the second selection, we will see that no, the first selection can not depend on a selection that <u>did not happen yet.</u>
So the situation is:
We have a group of puppies, some are black, some are white.
Let's say that there are N puppies in total, n₁ are black, n₂ are white, such that:
n₁ + n₂ = N
Now we have that the first selection, event A, is a black puppy. The probability is just the quotient between the number of black puppies and the total number of puppies:
q = n₁/N
Then now we have:
- N - 1 puppies in total.
- n₁ - 1 black puppies
- n₂ white puppies.
Now for the second selection, event B, the probability of selecting a white puppy is:
P = n₂/(N - 1)
Notice that because there are fewer black puppies than before (because we took one) the denominator decreases, thus, the probability of getting a white puppy increases.
So clearly event B depends on event A.
Now the question is:
Is A dependent on B?
No, A can not depend on event B, because event A happens first. The probability of the first event is always q = n₁/N.
If you want to learn more, you can read:
brainly.com/question/12138717
