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3 years ago

Find the slope of the line that contains the points (6,-3) and (6,5)

2 answers:

3 0

You would have to use the slope formula y2-y1/x2-x1 and substitute the values into this. That would be 5+3/6-6 which is 8/0. 0 can’t be in the denominator because no number can be divided by 0 so the slope is undefined.

sergiy2304 [10]3 years ago

3 0

The slope is undefined because u can’t divide a number by 0

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Mr. Diaz is building a fence around his yard. For numbers 3a-3b, choose the values and term that correctly describe the shape of

Inga [223]

3a) The figure has 5 sides and 5 vertices

3b) None of the sides are congruent, so the figure is not are guitar polygon

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3 years ago

The measure of one base angle of an isosceles triangle is 35 degrees. What is the measure of the vertex angle?

Elis [28]

Answer:

110 degrees

Step-by-step explanation:

The measures of the two base angles of an isosceles triangle are the same so 180 - 2(35) = 110 which is the vertex angle.

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3 years ago

How can 17/20 and 7/4 make a sum of 9/10

Anika [276]

Answer:

the answer is $\frac{35}{20}$

Step-by-step explanation:

You have to find the common denominator in order to get the sum.

multiply 5 to $\frac{7}{4}$ and you get $\frac{35}{20}$

then to double check the sum, subtract it.

$\frac{35}{20}-\frac{17}{20}=\frac{9}{10}$

hope this make sense :/

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3 years ago

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

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3 years ago

What is the midpoint of the segment shown below?

a_sh-v [17]

B because it is the midpoint for segment shown above

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3 years ago