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alex41 [277]
3 years ago
5

Find the slope of the line that contains the points (6,-3) and (6,5)

Mathematics
2 answers:
kobusy [5.1K]3 years ago
3 0
You would have to use the slope formula y2-y1/x2-x1 and substitute the values into this. That would be 5+3/6-6 which is 8/0. 0 can’t be in the denominator because no number can be divided by 0 so the slope is undefined.
sergiy2304 [10]3 years ago
3 0
The slope is undefined because u can’t divide a number by 0
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Find the slope: (-4, 3) and (8, -3)
olga2289 [7]

Answer:

-1/2

Step-by-step explanation:

The slope is the change in y over the change in x.

\frac{y_{2} -y_{1} }{x_{2} -x_{1} }

For this question:

\frac{3-(-3)}{-4-8} =\frac{6}{-12} =-\frac{1}{2}

4 0
3 years ago
Read 2 more answers
A function passes through the points (2,9) and (7,34). What are its rate of change and initial value?
Bess [88]

Answer:

The rate of change: 1/5

Initial value: (0,-1)

Step-by-step explanation:

The rate of change is easily 5/25, we just have to simplify it to 1/5.

To get the intial value, just subtract (2,9) by the rate of change twice.

5 0
3 years ago
Help me please I don’t know it
avanturin [10]
C both of these is correct
4 0
2 years ago
Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
2 years ago
The perimeter of a rectangle is 64cm.
Svet_ta [14]

Answer:

4cm

Step-by-step explanation:

28 + 28 = 56

64 - 56 = 8

8/2=4

just to check : 4 + 4 + 28 + 28 = 64

hope this helps x

brainliest plx?

6 0
3 years ago
Read 2 more answers
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