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dimaraw [331]
3 years ago
9

How do you solve for x when it's cubed?

Mathematics
1 answer:
uysha [10]3 years ago
4 0
Square root it to cancel out the 2
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Solve for n: n/3 > 66 2/3
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Tell whether each scale reduces, enlarges, or preserves the size of the actual object.
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Expand and simplify <br><br> A. (x – 2y)(y – 3x)<br><br> B. (2p+3)(p^2-4p-7)
emmasim [6.3K]

Answer:

A. (x−2y)(y−3x)

=(x+−2y)(y+−3x)

=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)

=xy−3x2−2y2+6xy

=−3x2+7xy−2y2

B. (2p+3)(p2−4p−7)

=(2p+3)(p2+−4p+−7)

=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)

=2p3−8p2−14p+3p2−12p−21

=2p3−5p2−26p−21

Hope it helps

Please mark me as the brainliest

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5 0
3 years ago
Which of the following statements is true in a one-way ANOVA? a. The critical value of the test will be a value obtained from th
Musya8 [376]

Answer:

d) All of the above

Step-by-step explanation:

A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).

In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.

In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.

This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.

The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.

Let's say we are comparing the means of k population. The degree of freedom would be = k - 1

The correct option here is (d).

All of the above

3 0
4 years ago
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