1 pts

Suppose that, in some distant part of the universe, there is a star with four orbiting planets . One planet makes a trip around

WINSTONCH [101]

Answer: 90 Earth years.

Step-by-step explanation:

Analizing the information provided in the exercise, you need to find the Least Common Multiple (LCM) of the given numbers.

You can follow these steps:

1. You must descompose 6, 9, 15 and 18 into their prime factors:

$6=2*3\\\\9=3*3=3^2\\\\15=3*5\\\\18=2*3*3=2*3^2$

2. Finally, you need to choose the commons and non commons with their greatest exponents and multiply them. Then you get:

$L.C.M=2*3^2*5=2*9*5\\\\L.C.M=90$

Therefore, it will take 90 Earth years for them to all line up.

3 0

3 years ago

Tamir wants to buy a snowboard. The original price is $760. How much will Tamir pay if he buys it during the sale?

grandymaker [24]

Depends on how much it’s on sale

4 0

3 years ago

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

6 0

3 years ago

5(x+2y)−3=3x+5 <br> 4(x−3y)−50=−33y <br><br> X=? Y=?

bekas [8.4K]

Answer:a

Step-by-step explanation:

3 0

4 years ago

Pleasee Help !!!!

lions [1.4K]

Hey dhsidvxhejfbeifbshdjdbd

8 0

4 years ago