Determine the intercepts of the line.

Mellisa is an expert scuba diver.she's down in the Pacific Ocean, looking for a rare type of sunfish. At one point, she is 29 me

Airida [17]

Answer:

A. 14 meters

B. 24 meters

Step-by-step explanation:

A. Mellisa starts at 29 meters deep, then rises 15 meters. So her final depth is 29 − 15 = 14 meters.

B. Melissa starts at 40 meters deep, then rises 2 m/min for 8 minutes. That means she rises a total distance of 2 × 8 = 16 meters. So her final depth is 40 − 16 = 24 meters.

8 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

3 years ago

How to reduce into simpler terms.?

Sveta_85 [38]

Answer:

The simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.

In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

$\frac{45}{100}$

$\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}$

$\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5$

$\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}$

$45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20$

so

$\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=\frac{9}{20}$

Therefore, the simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

4 0

4 years ago

Please help me !!!!

liq [111]

Answer:

...

against the wind, an airplane travels 3640 km in 7 hours.

with the wind, the same plane travels 6000 km in 6hrs.

...

let speed of plane in still air be x mph

speed of wind be y mph.

..

t=d/r

..

against wind speed = x-y mph

with wond speed = x=y mph

...

3640/(x-y)=7

3640 = 7x-7y

/7

520=x-y.....................1

...

6000/x+y = 6

6000 = 6x+6y

/6

1000=x+y.....................2

...

Add (1) & (2)

2x=1520

/2

x=760 mph speed of plane in still air

...

plug value of x in 2

1000=760+y

100-760=y

240 = y

240 mph speed of wind

8 0

3 years ago

Pls help me 10 points

yarga [219]

Ans8 up and 8 to the left basically 8.8

Step-by-step explanation:

4 0

3 years ago