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Y_Kistochka [10]
3 years ago
8

The lengths of three sides of a triangle are m units, n units, and p units, respectively. Which inequality must be true?

Mathematics
2 answers:
Bogdan [553]3 years ago
4 0

Answer:

n < m + p

Step-by-step explanation:

If ABC is a triangle then the sum of any two sides of ABC will be greater than the third side i.e. AB + BC > CA or BC + CA > AB or CA + AB > BC.

Now, if the lengths of three sides of a triangle are m units, n units, and p units respectively.  

Then the inequality must be true is n < m + p,  where m + p is the sum of any two sides which is greater than the third side of n length. (Answer)

alexdok [17]3 years ago
3 0

The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Therefore, the inequality that must be true is n < m + p.

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A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies
Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

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using standard normal table ,

\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}

Final Answer

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