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IgorLugansk [536]
3 years ago
12

In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.What

are the lower and upper limits of a box-and-whiskers display of this data?
Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

We conclude that the lower limit of a box-and-whiskers display is 65.

We conclude that the upper limit of a box-and-whiskers display is 77.

Step-by-step explanation:

Definition: A box-and-whisker plot or boxplot is a diagram based on the five-number summarytext annotation indicator of a data set.

In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.

We conclude that the lower limit of a box-and-whiskers display is 65.

We conclude that the upper limit of a box-and-whiskers display is 77.

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A hiker walks at a speed of 3 2/5 km per hour. how many km will he walk in 3/4 of an hour
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Answer:

2.55

Step-by-step explanation:

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3 years ago
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The height of the cactus is three times the height of the gate

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3 0
3 years ago
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What’s the answer to #12? and why
Elena L [17]
Remark
If there are 5 distinct zeros that means either that the x axis is crossed the x axis 5 different places or touched the x axis in 1 place out the 5. Touching in one place means that an even number of roots are the same. 

So let's go through all of them to get an answer of 5.

A has 4 x intercepts. It is not the right answer. We need 5.
B has 4 x intercepts. It is not the right answer. We need 5.
C has 6 x intercepts. Not the one we want.
D has 5 x distinct zeros. The wording is a bit tricky. It does not matter than one of them just touches the x axis. There could be an even number of distinct zeros there, but it only counts as one root.

An example of such a graph is f(x)=\left(\frac{1}{10}(x+2)(x+1.5)(x+1)(x-2)^4(x-3)\right)
 
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6 0
3 years ago
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The product of two consecutive positive integers is 56. Find the two integers
vredina [299]

Answer:

Two consecutive integers are of the form

x and x + 1

Their product is equal to 56

x(x + 1) = 56

Solve and find the two numbers x and x + 1. The above equation may be written as follows

x2 + x - 56 = 0

Factor and solve

(x - 7)(x + 8) = 0

solutions: x = 7 , x = -8

x= - 8 is not valid since the number sought must be positive. Hence

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Step-by-step explanation:

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wlad13 [49]
The square roots of 64 are -8 and +8.
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