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PolarNik [594]
3 years ago
8

Can someone plz help? It's algebra, and if you cant help, plz don't answer.

Mathematics
2 answers:
STatiana [176]3 years ago
6 0

Answer:

It is the last one

Step-by-step explanation:

skelet666 [1.2K]3 years ago
3 0

Answer:The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line

Step-by-step explanation:y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3

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Solve the system of equations using substitution.<br> y=x+2,5x-4y=-3
NARA [144]

Answer:

x=5 and y=7

Step-by-step explanation:

Just substitute in y=x+2 into the equation 5x-4y=-3 to get 5x-4(x+2)=-3 which simplifies to x=5. Substitute x into y=x+2 to find y=7

8 0
2 years ago
The area of a semicircle is 2 times the area of a circle. <br><br> True or False?
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That is false.  A semicircle is 1/2 a circle
3 0
3 years ago
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If an object that is 85 ft. long is represented on a scale drawing as a line 5 in. long, what is the scale used to make the draw
wolverine [178]
The answer is A.
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7 0
3 years ago
Nearest hundred thousand 700,00 what is the exact number
coldgirl [10]
It`s either 100,000 because there is only four 0`s making it 70,000 or it`s 700,000 and you made a mistake of not typing that last zero in which case the question would be pointless to ask because the answer is in the question.
6 0
3 years ago
2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th
coldgirl [10]

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

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Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

8 0
3 years ago
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