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3 years ago

Find the length of side x in simplest radical form with a rational denominator.

Mathematics

2 answers:

konstantin123 [22]3 years ago

6 0

Step-by-step explanation:

given length of hypotenuse, h=3 units.

adjascent angle for x is 45°

cos(45°)=x/3

cos(45°)=1/root 2(I dont have root symbol sorry)

1/root 2=x/3

x=3/root 2 units

x=3root 2/2

and hi pls comment

Misha Larkins [42]3 years ago

5 0

Answer:

x= 2/2

Step-by-step explanation:

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And angle measures 54° more than the measure of its complementary angle what is the measure of each angle

Mashutka [201]

Answer:
The measure of the angles are 72 degrees and 18 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
Let
x -----> the measure of an angle
y-----> the measure of he other angle
we know that
x+y=90 -----> y=90-x -----> equation A
x=y+54 ----> equation B
substitute equation B in equation A and solve for y
y=90-(y+54)
y=90-y-54
2y=36
y=18°
Find the value of x
x=y+54 -----> x=18+54=72°
therefore
The measure of the angles are 72 degrees and 18 degrees

4 0

3 years ago

a sixth grade student brought three cans of tennis balls for $4 each sales tax for all three cans was $0.95 write an expression

JulijaS [17]

Answer:

An expression that would show how much the student paid is 3(4) + 0.95, which can be solved to be 12.95

Step-by-step explanation:

We know that we need to multiply the number of cans (3) by the price of the cans (4). We also know the sales tax for the total is 0.95, which can simply be added to the end.

8 0

3 years ago

Find the area of a rectangle that is 17 3/8 in. By 4 1/9 in.

timama [110]

Answer:

71 31/72 in

Step-by-step explanation:

multiply the length and width for the formula. :)

4 0

3 years ago

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

vichka [17]

Answer:

$x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-10 and c=6

Putting values in the quadratic formula

$x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}$

So, $x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

3 0

3 years ago

Read 2 more answers

ONE more question Ah

Setler [38]

Answer: I don’t understand?

Step-by-step explanation:

6 0

3 years ago