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olasank [31]
2 years ago
15

What is the value of x? B 75° Enter your answer in the box. X= 50° с х

Mathematics
1 answer:
Klio2033 [76]2 years ago
4 0

Answer: x= 55°

Step-by-step explanation:

Angles in a triangle always add up to 180°.

As you are already given 2 of the 3 angles, all you need to do is add up the 2 given angles and take them away from the total (180°) to find the last angle.

75+50= 125

180-125= 55°

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Find the 4 digit code btw its not 5396 or 6935
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I think it would be 3569 , i’m not sure tho.
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3 years ago
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Find the length of the segment with endpoints of (3, 2) and (-3, -6).
nevsk [136]

The distance between (3, 2) and (-3, -6) is 10 units

The correct answer is B) 10

Further explanation:

Given points are:

(x1,y1) = (3,2)

(x2,y2)=(-3,-6)

The distance formula is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Putting the values

d=\sqrt{(-3-3)^2+(-6-2)^2}\\=\sqrt{(-6)^2+(-8)^2} \\=\sqrt{36+64}\\ =\sqrt{100}\\d=10

The distance between (3, 2) and (-3, -6) is 10 units

Keywords: Magnitude, Distance

Learn more about magnitude at:

  • brainly.com/question/12876715
  • brainly.com/question/12933539

#LearnwithBrainly

8 0
4 years ago
Nada is making square coasters with sides of 3 inches. On each coaster is a circular design. What is the radius of the largest c
Brilliant_brown [7]

Answer:

2.25π square inches [or 7.07 sq. in. rounded to 2 decimal places]

Step-by-step explanation:

The largest circle inscribed in a square would have DIAMETER EQUAL TO THE SIDE LENGTH OF THE SQUARE.

Since diameter is double of radius, we can find the radius to be:

diameter = 3 [side length of square]

radius = 3/2 = 1.5 inches

The area of a circle is  πr^2

THus, the largest circle area = πr^2 = π(1.5)^2 = π(2.25) = 2.25π square inches

4 0
4 years ago
2. Solve the equation using the quadratic<br> formula.<br> -4x2 + 40x + 16 = 0<br> Page 1 of 2
kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

-4x^2 + 40x + 16 = 0

To find: solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0
3 years ago
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